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How much greater is the area of a circle with a radius of 6.2 inches than the area of a square with a side length of 4 inches?

1 Answer

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Answer:

7.54 times greater.

Explanation:

The square with a side length of 4 inches has a 4×4=16 inches squared area. The area of a cirkel is calculated with the formula \pi×r^2. Using the 6.2 inch radius given, we get \pi×6.2^2=120.76 inches squared. 120.76/16=7.54 times greater.

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