18.6k views
4 votes
A rectangle has a perimeter of 50 m and a side length of L.

a. Express the other dimension of the rectangle in terms of L. ​

User Tim Tom
by
8.8k points

2 Answers

5 votes

Answer: The other dimension can be expressed as

(50 - 2L)/2

Step-by-step explanation: First and foremost, we would let the other dimension be represented by B. Then, the perimeter of a rectangle is measured as L+L+B+B or better put;

Perimeter = 2L + 2B

Where L is the measurement of the longer side and B is the measurement of the shorter side.

In this case the perimeter of the rectangle measures 50m, and this can now be written as

50 = 2L + 2B

Subtract 2L from both sides of the equation

50 - 2L = 2L - 2L + 2B

50 -2L = 2B

Divide both sides of the equation by 2

(50 - 2L)/2 = B

User Marshal
by
8.1k points
4 votes

Answer:

25-L

Explanation:

Let W represent the other side length. The perimeter (P) of the rectangle is ...

P = 2(W+L)

Solving for W, we get ...

P/2 = W+L

P/2 -L = W

Filling in the given value for P, we find ...

W = 50/2 -L = 25 -L

The other dimension is (25-L) meters.

User Taria
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories