Question

The repulsive force between two protons has a magnitude of 2.00 N. What is the distance between them?

A. 1.07 x 10^-14 m
B. 1.28 x 10^-38 m
C. 7.19 x 10^-10 m
D. 2.68 x 10^-4 m

Answer 1

A

Step-by-step explanation:

Using F = kq1q2/r^2

r^2 = kq1q2/F

r = square root of (kq1q2/F)

r = square root of(8.99 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19/2)

r = square root of(1.15072 x 10^-28)

r = 1. 07 x 10^-14m

Answer 2

The answer to your question is letter A. r = 1.07 x 10⁻¹⁴ m

Step-by-step explanation:

Data

F = 2 N

d = ?

q = 1.6 x 10 ⁻¹⁹ C

k = 8.987 Nm²/C²

Formula

`F = K(q1q2)/(r^(2))`

Solve for r

`r = \sqrt{(kq1q2)/(F)}`

Substitution

`r = \sqrt{(8.987 x 10^(9)x1.6 x 10^(-19) x 1.6 x 10x^(-19))/(2)}`

Simplification

r =
`\sqrt{(2.3 x 10^(-28))/(2)}`

r =
`\sqrt{1.15 x 10^(-24)}`

Result

r = 1.07 x 10⁻¹⁴ m