Question

Use the slope-intercept form of the linear equation to write the equation of the line with the given slope and y-intercept. Slope 4; y-intercept (0,-8/9)

Type answer in slope-intercept form

Answer 1

`\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{-(8)/(9)}) ~\hspace{10em} \stackrel{slope}{m}\implies 4 \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\left(-\cfrac{8}{9} \right)}=\stackrel{m}{4}(x-\stackrel{x_1}{0}) \\\\\\ y+\cfrac{8}{9}=4x\implies y = 4x-\cfrac{8}{9}`

Answer 2

Slope-intercept form: y = mx + b [m is the slope, b is the y-intercept or the y value when x = 0 ---> (0, y)]

Since you know:

m = 4

`b=-(8)/(9)` Plug it into the equation

y = mx + b

`y=4x-(8)/(9)`