Answer:
B. 159.6 g
Step-by-step explanation:
balanced reaction:
∴ moles taht react of Fe = 2 mol
∴ mm Fe = 55.845 g/mol
⇒ g Fe2O3 = ?
∴ moles Fe2O3 = ( 2 mol Fe )×( 2 mol Fe2O3/ 4 mol Fe ) = mol Fe2O3
∴ mm Fe2O3 = 159.6882 g/mol
⇒ g Fe2O3 = ( 1 mol Fe2O3 )×( 159.6882 g/mol) = 159.6882 g