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A ball is dropped off the side of a bridge. after falling 1.55 s, what is its velocity?

A ball is dropped off the side of a bridge. after falling 1.55 s, what is its velocity-example-1

2 Answers

4 votes

Answer:

-15.19

Step-by-step explanation:

User Vorobey
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4.6k points
4 votes

Answer:

-15.19 m/s

Step-by-step explanation:

The 1D kinematic equation for velocity is the v = v0 * at.

In this case, v is the final velocity (what we're after), v0 is the initial velocity, a is the acceleration, and t is the time elapsed.

v0 is 0 because at 0 seconds we are just releasing the ball.

a is the acceleration due to gravity as no other factors are specified.

t is the change in time.

v = 0 * -9.8 m/s^2 * 1.55 = -15.19 m/s.

User Mike Flynn
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