20.0k views
1 vote
Help me out with this

Help me out with this-example-1
User Elimirks
by
8.4k points

1 Answer

6 votes

Let's follow the transformations that happen to A, to get to A' and A''.

Point A is at (-5, -2)

It moves to (-5, 2) which is where A' is located. Note the x coordinate stays the same while the y coordinate flips from negative to positive. This must mean we applied a reflection over the x axis.

That rule in general is
(x, y) \rightarrow (x,-y)

------------------------------------

Now compare A'(-5,2) and A''(1,4). We can shift A' 6 units to the right and then 2 units up so we move from A' to A''.

Algebraically this is stated as
(x,y) \rightarrow (x+6, y+2)

Whatever the x coordinate is, add 6 to it. For the y coordinate, we add on 2.

Applying that rule to B'(-1,2) gets us to


(-1,2) \rightarrow (-1\textbf{+6}, 2\textbf{+2}) = (5,4)

which is the proper location of B''

The same applies to moving C' to C''


C' = (-5, 0) \rightarrow (-5\textbf{+6}, 0\textbf{+2}) = (1, 2) = C''

-------------------------------------------

In summary, we started off by reflecting over the x axis. Then we applied the translation rule of "shift to the right 6 units, shift up 2 units".

In terms of algebra, combining the rules
(x,y) \rightarrow (x,-y) and
(x,y) \rightarrow (x+6, y+2) will have us end up with
(x,y) \rightarrow (x+6, -y+2)

User Trystan Sarrade
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories