Answer:
![16.2\ (rev)/(min)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y2stvrg2nqebfptsdga9bks9ephto7azsw.png)
Explanation:
The complete question is
A hamster runs at 17 centimeters per second in a wheel of radius 10 centimeters how fast will the wheel spin in revolutions per minute?
step 1
Find the circumference of the wheel
The circumference of the circle is equal to
![C=2\pi r](https://img.qammunity.org/2021/formulas/mathematics/middle-school/mi4tnw17egix4j0slvrtb6r082cjra53zk.png)
we have
![r=10\ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/egmg3xq75v8gdmi0le9qj0jfwbmv3nynjk.png)
substitute
![C=2\pi (10)\\C=20\pi\ cm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/zciwrzscjbzs7kx1quk1d1su1feid22bxo.png)
assume
![\pi=3.14](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rl6dh8czfqdfue9fciig8t9lofe1lzq2pb.png)
![C=20(3.14)=62.8\ cm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rks27q64nnvh7jwjujsl50lvazirjqs3i6.png)
step 2
Find the number of revolutions
Remember that
One revolution of the wheel represent a distance equal to the circumference of the wheel
using proportion
![(1)/(62.8)\ (rev)/(cm)=(x)/(17)\ (rev)/(cm)\\\\x=17/62.8\\\\x=0.27\ rev](https://img.qammunity.org/2021/formulas/mathematics/middle-school/x1f6dfcn50nw5bigm39eul0hucwmy17cow.png)
so
The number of revolutions per second is
![0.27\ (rev)/(sec)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jnsfz8mqylfoddv8byxi1tgxy7dzfbcj9h.png)
step 3
Convert to rev per minute
we know that
![1\ min=60\ sec](https://img.qammunity.org/2021/formulas/mathematics/middle-school/a49kx996nu2x20r3ncvdn1cfmo9m2z522h.png)
to convert sec to min divide by 60
so
![0.27\ (rev)/(sec)=0.27:(1)/(60)=16.2\ (rev)/(min)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/iqmt3nlib48m3u6wwcuo8179r4ekzrpi2n.png)