Question

The length of a rectangular garden is 6 m greater than the width. The area of the garden is nbsp 72 m squared . Find the dimensions of the garden.

The width of the garden is
nothing
▼
m.
m cubed .
m squared .

Answer 1

The width of the rectangular garden is 6 m, and the length is 12 m. These dimensions satisfy the condition that the area is 72 m² and the length is 6 m greater than the width.

Step-by-step explanation:

To find the dimensions of the rectangular garden where the length is 6 m greater than the width and the area is 72 m², we can let the width be w meters. Then the length would be w + 6 meters. The area (A) of a rectangle is given by the formula A = length × width, so we can set up the equation w(w + 6) = 72 to find the value of w.

Solving the quadratic equation,

w² + 6w = 72

w² + 6w - 72 = 0

Factor the quadratic equation to find the values of w.

(w + 12)(w - 6) = 0

Set each factor equal to zero and solve for w: w + 12 = 0 or w - 6 = 0

This gives us w = -12 or w = 6. Since width cannot be negative, we choose w = 6 m.

Therefore, the width of the garden is 6 m, and the length is 6 m + 6 m = 12 m.

Answer 2

Equation=2m+6=72sq^2

First step would be to cancel out the 6 in the equation to isolate the m.
So 6-6=0 and you always have to apply that to the answer so 72-6 which is equal to 66.

Now the m’s are isolated. To find out the value of m them divide it by 2 to give you one solitary m, and as said before apply that to the 66.

2m/2=m & 66/2=33. The expression now reads m=33. So m=33m^2(squared)