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Evaluate log base 12 of y^2, given log base 12=16

User Eylon
by
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1 Answer

2 votes

Answer:

y = 12^8

Explanation:

Log base 12, y^2 = 16

y2 = 12^16

y = sqrt ( 12^16) = (12^16)^1/2

y = 12^8

User Yonghoon Lee
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