sinФ = 1/6
sinФ = opposite/hypotenuse
cosФ = adjacent/hypotenuse
tanФ = opposite/adjacent
SOHCAHTOA
1^(2)+b^(2)=6^(2)
1+b^(2)=36
b^(2)=35
cosФ = /6
tanФ = 1/ = /35
Answer:
Cos ø = √35/6
Tan ø = √35/35
Explanation:
Sin ø = opposite/hypothenus
Sin ø = 1/6
Pythagoras theorem says
Hyp² = Opp² + Adj²
6² = 1² + A²
A² = 35
A = √35
Hence, cos ø = √35/6
tan ø = 1/√35 = √35/35
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