Question

What are the x- and y-intercepts of -6x+4y=96

Answer 1

`\text{Find the x and y intercepts:}\\\\\text{x intercepts:}\\\\\text{Plug in 0 to y}\\\\-6x+4(0)=96\\\\\text{Solve:}\\\\-6x+4(0)=96\\\\-6x=96\\\\\text{Divide both sides by -6}\\\\\boxed{x=(-16,0)}\\\\\text{y intercept:}\\\\\text{Plug in 0 to x}\\\\-6(0)+4y=96`

`\text{Solve:}\\\\-6(0)+4y=96\\\\4y=96\\\\\text{Divide both sides by 4}\\\\\boxed{y=(0,24)}`

Answer 2

Explanation:

to find the x intercept, sub in 0 for y and solve for x

-6x + 4y = 96

-6x + 4(0) = 96

-6x = 96

x = -96/6

x = -16.....ur x intercept is -16 or (-16,0) <===

to find the y intercept, sub in 0 for x and solve for y

-6x + 4y = 96

-6(0) + 4y = 96

4y = 96

y = 96/4

y = 24....so ur y int is 24 or (0,24) <===