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A 0.25 kg ideal harmonic oscillator has a total mechanical energy of 9.8 J. If the oscillation amplitude is 20.0 cm, what is the oscillation frequency?a. 4.6 Hz b. 1.4 Hz c. 2.3 Hz d. 3.2 Hz

User Rogerthat
by
8.6k points

1 Answer

5 votes

Answer:

7.04 Hz

Step-by-step explanation:

x(t) = A cos(wt)

v(t) = - wA sin (wt)

Vmax = wA

E = 1/2 * m * (Vmax)^2

E = 1/2*m*(wA)^2


w = (1)/(A) \sqrt{(2E)/(m) }

f = w/ 2*pi


f = (1)/(2*pi*A)*\sqrt{(2E)/(m) } \\f = (1)/(2 * pi * 0.2)*\sqrt{(2(9.8))/(0.25) } \\f = 7.04 Hz

User Vitali Kniazeu
by
7.5k points
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