71.7k views
4 votes
A 435-gram baseball traveling at 36 m/s is hit directly back at the pitcher with a speed of 49 m/s. If the force of contact between the bat and the ball is 3500 Newtons, then the ball is in contact with the bat for a time of_______________.

A. 1.615714286
B. Incorrect
C. seconds.
D. 3.

1 Answer

1 vote

Answer:

t = 0.0105 s

Step-by-step explanation:

given,

mass of the baseball = 435 g = 0.435 Kg

initial speed of ball, u = 36 m/s

final speed of ball, v = 49 m/s

contact force , F = 3500 N

we know,

Impulse is equal to change in momentum

I = m v - m u

I = 0.435 (49-(-36))

I = 0.435 x 85

I = 36.975 kg.m/s

we also know that

I = F x t

36.975 = 3500 x t

t = 0.0105 s

time of contact is equal to 0.0105 s

User Abdullah Saleem
by
4.1k points