Question

Knowing the P is 1110 N, determine the tension in the rope if the frame is in equilibrium. Express your answer in kN to the nearest 10 N.

Answer 1

Step-by-step explanation:

It is given that the value of P is 1110 N. And, for pin connection we have only two connections which are
`A_(x)` and
`A_(y)`. Let T be the tension is rope.

So,
`\sum F_(y) = 0` and
`A_(y)` - 1110 = 0

`A_(y) = 1110 N`

`\sum F_(x)` = 0

And,
`T - A_(x)` = 0

T =
`A_(x)`

Also,
`\sum M_(A)` = 0

1110(0.75 + 0.75 + 0.75) - T(0.5 + 0.1) = 0

2497.5 - 0.6T = 0

T = 4162.5 N

= 4.16 kN

Therefore, we can conclude that the tension in the rope if the frame is in equilibrium is 4.16 kN.