Answer:
![Width = 2(1)/(4)cm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/g9ypg2e5sgi8eqasla7584bvebkrl7narc.png)
![Length=5(5)/(12) cm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/g25is53i3bkjanc9ic6det0r8n8zy3srg7.png)
Explanation:
Data from the question;
Perimeter of a rectangle is
cm
Length is
cm longer than the width
We are supposed to determine the length and the with of the rectangle;
Assuming, the width x cm
Then, the length is
cm
We need to know that the perimeter of a rectangle is given by;
Perimeter = 2 ( length + width)
Therefore;
![15(1)/(3)= 2 ( x + (x+3(1)/(6)))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/x91fz3bdm1mgveoxnealr5qv6m5fco4ir5.png)
![15(1)/(3)=2(2x+3(1)/(6))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jt1olr5sohqlnspk8qyq51kcwusjzi78o0.png)
Thus;
![15(1)/(3)=4x+6(1)/(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/39aicv8nmpui5nyqbtdbyf72mtcumaw8sf.png)
![4x=9\\x=2(1)/(4)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8si74ferh1t1sit1wtr4apr8o3ysmjw0xz.png)
Therefore;
![Width = 2(1)/(4)cm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/g9ypg2e5sgi8eqasla7584bvebkrl7narc.png)
![Length = x + 3(1)/(6)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/mnmkpg7ww09uthl0j5lv5mjmm84psj1j4s.png)
![=2(1)/(4)+3(1)/(6)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jfeq822beb9omld31kzh8m7k616ncbj30c.png)
![=5(5)/(12) cm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rg0qzc5n3752fv95dakfqfmbn8w1uofeq1.png)
Therefore; the length is
cm while the width is
cm