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Dimensions of a rectangle whose length is 8 more than twice it’s width and has a perimeter of 40 cm.

User Neetu
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1 Answer

5 votes

Answer:

Width = 4 cm

Length = 16 cm

Explanation:

We are given;

  • Perimeter = 40 cm
  • Assuming the width is x
  • Then, length is 2x + 8 ( 8 more than twice the width)

We are required to determine the dimensions of the rectangle;

  • We need to know that the perimeter of the rectangle is given by;
  • Perimeter = 2 (length + width)

In this case;

2 ( 2x + 8 + x) = 40

2 ( 3x + 8 ) = 40

6x + 16 = 40

6x = 24

x = 4

Thus; the dimensions of the rectangle are;

Width = 4 cm, and

Length = 16 cm

User Dmitriy Stupivtsev
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