Question

Calculate the volume in liters of a ×7.7310−5/mmolL silver(II) oxide solution that contains 475.μmol of silver(II) oxide AgO . Round your answer to

3 significant digits.

Answer 1

Answer: Thus volume in liters is
`6.14* 10^3L`

Step-by-step explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

To calculate the number of moles for given molarity, we use the equation:

`\text{Molarity of the solution}=\frac{\text{Moles of silver oxide}}{\text{Volume of solution in L}}` .....(1)

Molarity of silver oxide solution =
`7.73* 10^(-5)mmol/L=7.73* 10^(-2)\mu mol/L`
`1mmol=1000\mu mol`

Moles of silver oxide =
`475\mu mol`

Volume of solution in L = ?

Putting values in equation 1, we get:

`7.73* 10^(-2)\mu mol\L=\frac{475\mu mol}{\text{Volume of solution in L}}\\\\\{\text{Volume of solution in L}}=(475\mu mol)/(7.73* 10^(-2)\mu mol\L)=6.14* 10^3L`

Thus volume in liters is
`6.14* 10^(3)L`