Question

A room is cooled by circulating chilled water through a heat exchanger located in the room. The air is circulated through the heat exchanger by a 0.25-hp (shaft output) fan. Typical efficiency of small electric motors driving 0.25-hp equipment is 60 percent. Determine the rate of heat supply by the fan–motor assembly to the room.

Answer 1

input power of the geothermal motor will be 0.4166 hP

Step-by-step explanation:

We have given shaft output = 0.25 hP

hP is known as horse power which is unit of measuring the power of motor

Efficiency of motor is given as efficiency = 60 % = 0.6

We have to fond the heat supply by the fan motor Q

We know that efficiency of any motor is the ratio of shaft power and input power

So
`0.6=(0.25)/(P_0)`

So
`P_0=(0.25)/(0.6)=0.4166hP`

So input power of the geothermal motor will be 0.4166 hP