Answer:
b. 0.1216
Explanation:
Given that a sample of 15 from a normal population yields a sample mean of 43 and a sample standard deviation of 4.7.
We have to check the p value for the claim that mean <45
(Left tailed test for population mean)
Sample size n = 15
Sample mean = 45
Sample std dev s = 4.7
Since sample std deviation is being used, we use t test only
Std error of mean =
Mean difference = 43-45 = -2
t statistic = mean difference/std error
= -1.176
df = n-1 = 14
p value = 0.1216