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Two cards are drawn from a standard deck without replacement. What is the probability that the first card is a club and the second card is red? (

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Answer:

Probability to draw a club and second card is red without replacement will be
(13)/(102) or 12.75%

Explanation:

A standard deck of cards contains number of cards = 52

And a standard deck contains number of club = 13

Now the probability of first card to be a club will be


P_(1)=\frac{\text{Number of club in a deck}}{\text{Total number of cards}}

=
(13)/(52)=(1)/(4)

Now this card is separated from the deck.

Therefore, number of remaining cards = 52 - 1 = 51

Second card has been drawn from the deck without replacement.

Since number of red cards in the deck = 13 + 13 = 26

Probability of the second card drawn =
\frac{\text{Number of red cards}}{\text{Number of remaining cards}}


P_(2)=(26)/(51)

Now probability that the first card is a club and the second card is red =
P_(1)* P_(2)=(1)/(4)* (26)/(51)

=
(13)/(102)

Or
(13)/(102)* 100=12.75%%

Therefore, probability to draw a club and second card is red without replacement will be
(13)/(102) or 12.75%

User DrewT
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