Answer:
Probability to draw a club and second card is red without replacement will be
or 12.75%
Explanation:
A standard deck of cards contains number of cards = 52
And a standard deck contains number of club = 13
Now the probability of first card to be a club will be
![P_(1)=\frac{\text{Number of club in a deck}}{\text{Total number of cards}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/329k44gxrc4hb3jym0gj8vzb4bigl33c8p.png)
=
![(13)/(52)=(1)/(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/gqekwhcz25kkgikhtn93qjdnmmpc2y03y0.png)
Now this card is separated from the deck.
Therefore, number of remaining cards = 52 - 1 = 51
Second card has been drawn from the deck without replacement.
Since number of red cards in the deck = 13 + 13 = 26
Probability of the second card drawn =
![\frac{\text{Number of red cards}}{\text{Number of remaining cards}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/v84vlhqgb5nu7ftun2kvftm9y4lqxazg92.png)
![P_(2)=(26)/(51)](https://img.qammunity.org/2021/formulas/mathematics/high-school/nnsby0url8b0ls98qoh4y0depkr25una3i.png)
Now probability that the first card is a club and the second card is red =
![P_(1)* P_(2)=(1)/(4)* (26)/(51)](https://img.qammunity.org/2021/formulas/mathematics/high-school/my95h6aiplki04lg8lrg66wv7c6d4fy8aq.png)
=
![(13)/(102)](https://img.qammunity.org/2021/formulas/mathematics/high-school/gc7c0wzyaov3uki0yfd3u8k0zvolnoot7q.png)
Or
%
Therefore, probability to draw a club and second card is red without replacement will be
or 12.75%