Question

What is the equation of a line that passes through the point (10, 5) and is perpendicular to the

line whose equation is y= x-2?
Enter your answer in the box.

Answer 1

y = -x + 15

Explanation:

y = x-2

slope = 1

perpendicular line slope = -1

pass point (10, 5)

y intercept = y - mx = 5 - (-1)x10 = 15

equation: y = mx + b

y = -x + 15