Answer:
a) The sample range 25.9

b) The sample variance is 49.344

c) The sample standard deviation 7.0245
Explanation:
We are given the following data on oxygen consumption (mL/kg/min):
28.6, 49.4, 30.3, 28.2, 28.9, 26.4, 33.8, 29.9, 23.5, 30.2
a) The sample range
Range = Maximum - Minimum

The sample range 25.9

b) The sample variance
where
are data points,
is the mean and n is the number of observations.


Sum of squares of differences =
5.3824 + 341.5104 + 0.3844 + 7.3984 + 4.0804 + 20.4304 + 8.2944 + 1.0404 + 55.0564 + 0.5184 = 444.096

The sample variance is 49.344

c) The sample standard deviation
It is the square root of sample variance.

The sample standard deviation 7.0245
