Question

Two point charges exert a 7.35 N force on each other. What will the force become if the distance between them is increased by a factor of 2

Answer 1

New force becomes, F' = 1.83 N

Step-by-step explanation:

Let two point charges exert a force of 7.35 N force on each other. The electric force between two charges is given by :

`F=(kq_1q_2)/(r^2)`

`q_1\ and\ q_2` are charges

r is the distance between charges if the distance between them is increased by a factor of 2, r' = 2r

New force is given by :

`F'=(kq^2)/(r'^2)`

`F'=(kq^2)/((2r)^2)`

`F'=(1)/(4)(kq^2)/(r^2)`

`F'=(1)/(4)* 7.35`

F' = 1.83 N

So, the new force between charges will be 1.83 N. Therefore, this is the required solution.