Question

Two identical conducting small spheres are placed with their centers 0.290 m apart. One is given a charge of 12.0 nC and the other a charge of -21.0 nC.Find the electric force exerted by one sphere on the other.

Answer 1

Force between two identical conducting ball will be
`2.65* 10^(-5)N`

Step-by-step explanation:

We have given there is two identical conducting small spheres having charge
`q_1=12nC=12* 10^(-9)C` and
`q_2=-21nC=-21* 10^(-9)C`

Distance between centers of the ball is 0.290 m

So r = 0.290 m

We have to fond the electric force between the balls

According to Coulomb's law force between two charges is given by

`F=(1)/(4\pi \epsilon _0)(q_1_2)/(r^2)=(Kq_1q_2)/(r^2)`

So force
`F=(9* 10^(9)* 12* 10^(-9)* 21* 10^(-9))/(0.293^2)=2.65* 10^(-5)N`

So force between two identical conducting ball will be
`2.65* 10^(-5)N`