Question

so they are asking me to find the empirical formula for a compound that is 7.70% carbon and 92.3% chlorine. Can you show me step by step how to solve this step

Answer 1

Empirical formula is CCl₄

Step-by-step explanation:

Given data:

Percentage of carbon = 7.70%

Percentage of chlorine = 92.3%

Empirical formula = ?

Solution:

Number of gram atoms of Cl = 92.3 / 35.5 = 2.6

Number of gram atoms of C = 7.70 / 12 = 0.64

Atomic ratio:

C : Cl

0.64/0.64 : 2.6/0.64

1 : 4

C : Cl = 1 : 4

Empirical formula is CCl₄.