Question

An object of mass 0.67 kg is attached to a spring with spring constant 15 N/m. If the object is pulled 14 cm from the equilibrium position and released.

What is the maximum speed of the object?

Answer 1

The maximum speed of the object is 0.662 m/s.

Step-by-step explanation:

Given that,

Mass of the object, m = 0.67 kg

Spring constant of the spring, k = 15 N/m

The spring is pulled 14 cm or 0.14 m from the equilibrium position and released.

To find,

The maximum speed of the object.

Solution,

The maximum speed of the object is given by :

`v=A\omega`........(1)

Where

`\omega=\sqrt{(k)/(m)}`

`\omega=\sqrt{(15)/(0.67)}`

`\omega=4.73\ rad/s`

So,

`v=0.14* 4.73`

v = 0.662 m/s

So, the maximum speed of the object is 0.662 m/s.