Answer:
The Inequality modelling the equation is
.
The cafeteria typically serve lunch for students between 425 to 523.
Explanation:
Given:
Each students pays for lunch = $2.75
Cafeteria brings between $1168.75 and $1438.25.
We need to find the number of students cafeteria typically serve.
Solution:
Let the number of student served be 'x'.
Now we can say that;
Total money make is equal to Each students pays for lunch multiplied by number of students served.
But total money made is in the form of range so we can say that;
![1168.75\leq 2.75x\leq 1438.25](https://img.qammunity.org/2021/formulas/mathematics/high-school/5qap1may0lkt4svyqbqtapv4gulm8bsia1.png)
Now Dividing all sides by 2.75 we get;
![(1168.75)/(2.75)\leq (2.75x)/(2.75)\leq (1438.25)/(2.75)\\\\425\leq x\leq 523](https://img.qammunity.org/2021/formulas/mathematics/high-school/aq0abdj5jf63diowq8nbsyl1v8g3qrvb7i.png)
Hence the Inequality modelling the equation is
.
Hence we can say that, The cafeteria typically serve students between 425 to 523.