Question

Calculate the energy, in electron volts, of a photon whose frequency is the following.

(a) 585 THz
(b) 3.50 GHz
(c) 40.0 MHz

Planck's equation for the energy of a photon is E = hf, where f is the frequency and h is Planck's constant. We use 1 eV = 1.60 ✕ 10−19 J for units of energy.

(a) For the energy of the photon at a frequency of 585 THz, we have E = hf

Answer 1

(a)
`E=2.42eV`

(b)
`E=1.45*10^(-5)eV`

(c)
`E=1.66*10^(-7)eV`

Step-by-step explanation:

The Planck-Einstein relation allows us to know the energy (E) of a photon, knowing its frequency (f). According to this relation, the energy of the photon is defined as:

`E=hf`

Here h is the Planck constant.

(a)

`E=(4.14*10^(-15)eV\cdot s)(585*10^(12)Hz)\\E=2.42eV`

(b)

`E=(4.14*10^(-15)eV\cdot s)(3.50*10^(9)Hz)\\E=1.45*10^(-5)eV`

(c)

`E=(4.14*10^(-15)eV\cdot s)(40.0*10^(6)Hz)\\E=1.66*10^(-7)eV`