Question

A 880 N crate rests on the floor. (a) How much work is required to move it at constant speed 4.8 m along the floor against a friction force of 180 N?

Answer 1

We have to do 864 J for moving the crate

Step-by-step explanation:

We have given a 880 N crate is at rest on the floor

Frictional force f = 180 N

We have to move the crate by 4.8 m

For moving the crate we have to overcome the frictional force acting the crate

We know that work done is given by
`Work\ done=force* distance`

Here force will be equal to frictional force and distance is 4.8 m

So work done
`W=180* 4.8=864J`

So we have to do 864 J for moving the crate