Question

You throw a ball straight up at 45 m/s. How many elapse before it is traveling at 5 m/s?

Answer 1

Answer: 4.08 s

Step-by-step explanation:

We can solve this problem with the following equation:

`V=V_(o)-gt`

Where:

`V=5 m/s` is the final velocity of the ball

`V_(o)=45 m/s` is the initial velocity of the ball

`g=9.8 m/s^(2)` is the acceleration due gravity

`t` is the elapsed time

Isolating
`t`:

`t=-\frav{V-V_(o)}{g}`

`t=-\frav{5 m/s-45 m/s}{9.8 m/s^(2)}`

`t=4.08 s` This is the elapsed time