Answer:
238.2 g of CuBr₂ is the mass needed
Step-by-step explanation:
To work with molarity and volume, we can find the mass of solute as this
Molarity . volume (L) = moles → moles . molar mass = mass
1.25 mol/L . 0.750L = moles
0.9375 moles
0.9375 mol . 223.35 g/mol = 238.2 g of salt