Answer:
6 minutes
Explanation:
Let the volume of the sink be Xm^3
The rate of filling the sink by the first faucet is R1 while the rate of draining the faucet is -R2(negative since it’s draining)
R1 = x/2
R2 = -x/3 ( negative as it is draining)
The time it would take both of them working at the same rate to fill the sink is as follows:
x/(R1 - R2) = T
x/( x/2 - x/3) = T
x = T(x/2 - x/3)
x = T( (3x - 2x)/6)
x = T(x/6)
x = Tx/6
6x = Tx
T = 6 minutes