Answer:
(a) Mass flow rate is 2528.75 kg/min
(b) Molar flow rate is 458.1 mol/s
(c) Toulene is in-compressible at standard temperature and pressure
Step-by-step explanation:
The volume flow rate of liquid toulene is given:
Volume Flow Rate = 175 m^3/h
Density of Liquid Toulene = 867 kg/m^3
Molar mass of Toulene = 92 g/mol = 0.092 kg/mol)
(a)
Thus, the mass flow rate of toulene will be:
Mass Flow Rate = (Volume Flow Rate)(Density)
Mass Flow Rate = (175 m^3/h)(867 kg/m^3)
Mass Flow Rate = (151725 kg/h)(1 h/60 min)
Mass Flow Rate = 2528.75 kg/min
(b)
Now, for molar flow rate we use formula:
Molar Flow Rate = (Mass Flow Rate)/(Molar Mass)
Molar Flow Rate = (2528.75 kg/min)/(0.092 kg/mol)
Molar Flow Rate = (27486.41 mol/min)(1 min/60sec)
Molar Flow Rate = 458.1 mol/s
(b)
The assumption is that Toulene is in-compressible at standard temperature and pressure. So, that its density can be taken constant.