Question

A manufacture inspects 800 light bulbs and finds that 796 of them have no defects. What is the experimental probability that a light build chosen at random has no defects

Answer 1

The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.

Explanation:

let S be the sample space for the inspection of the light bulbs.

Therefore, n(s) = 800

let ' A ' be the event of no defects bulbs.

Therefore, n(A) = 796

Now the Experiment probability for a light bulb chosen has no defects will be given by,

`P(A)=(n(A))/(n(S))`

Substituting the values we get

`P(A)=(796)/(800)=0.995`

The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.