Question

A university campus has 200 classrooms and 400 faculty offices. The classrooms are equipped with 12 fluorescent tubes, each consuming 110 W, including the electricity used by the ballasts. The faculty offices, on average, have half as many tubes. The campus is open 240 days a year. The classrooms and faculty offices are not occupied for an average of 4 h a day, but the lights are kept on. If the unit cost of electricity is $0.115/kWh, determine how much the campus will save a year if the lights in the classrooms and faculty offices are turned off during unoccupied periods.

Answer 1

The campus will save approximately $58,124.80 per year if the lights in the classrooms and faculty offices are turned off during unoccupied periods.

Step-by-step explanation:

To determine how much the campus will save a year if the lights in the classrooms and faculty offices are turned off during unoccupied periods, we need to calculate the annual energy consumption and cost.

The classrooms consume 12 fluorescent tubes, each consuming 110 W. Since the faculty offices have half as many tubes, they consume 6 tubes on average.

First, let's calculate the annual energy consumption for the classrooms:

Energy consumption per classroom per day = (12 tubes) × (110 W/tube) × (4 h) = 5,280 Wh

Total energy consumption for all classrooms per day = (5,280 Wh/classroom) × (200 classrooms) = 1,056,000 Wh

Annual energy consumption for classrooms = (1,056,000 Wh/day) × (240 days) = 253,440,000 Wh = 253,440 kWh

Now, let's calculate the annual energy consumption for the faculty offices:

Energy consumption per office per day = (6 tubes) × (110 W/tube) × (4 h) = 2,640 Wh

Total energy consumption for all faculty offices per day = (2,640 Wh/office) × (400 offices) = 1,056,000 Wh

Annual energy consumption for faculty offices = (1,056,000 Wh/day) × (240 days) = 253,440,000 Wh = 253,440 kWh

Adding the energy consumption of the classrooms and faculty offices, the campus consumes a total of 506,880 kWh per year. To determine the cost savings, we need to multiply this by the unit cost of electricity:

Cost savings = (506,880 kWh) × ($0.115/kWh) = $58,124.80

Therefore, the campus will save approximately $58,124.80 per year if the lights in the classrooms and faculty offices are turned off during unoccupied periods.

Answer 2

Answer: The campus would save

$218.04.

Explanation: Total number of flourescent tubes in classroom is 12 and office is 6. The Electric Power consume by a single tube is 110W.

But,

Energy = Power * Time

For classroom energy consumed in a day that is 24hours would be

Energy = 12*110*24 = 31.7kwh

For office,

Energy = 6*110*24= 15.8kwh

Total Energy consumed at the campus for 24hrs{a full day} will be

Total Energy = 31.7kwh + 15.8kwh

= 47.5kwh.

In a year of activities at the campus given as 240days,

Energy consumed= 47.5kwh * 240

= 11400kwh.

The cost of 1kwh from the question is $0.115.

11400kwh will cost; 11400*$0.115

=$1,311

If the florescent tube are switched off for the 4hrs in a day the campus is not on session. Then we will have just 20hrs of usage in a day. So let's calculate;

Classroom,

Energy = 12*110*20= 26.4kwh

Faculty office,

Energy consumed = 6*110*20

= 13.2kwh

Total energy consumed in a day {20hrs}

= 26.4kwh + 13.2kwh= 39.6kwh.

In a year of activities at the campus given as 240days

Total Energy consumption would be

{39.6*240}kwh= 9504kwh.

The cost of 1kwh of electricity is $0.115.

Therefore, 9504kwh will cost;

$0.115 * 9504 = $1092.96.

This is more cheaper compared the the first one we calculated for 24hrs in a day.

So the campus will save;

$1,311 - $1092.96 = $218.04.

Which is the cost of energy of putting ON the flourescent tubes for 24hrs in a day minus the cost of putting them ON for just 20hrs in a day.