Answer: 9.9248
Explanation:
We know that the critical t- value for confidence interval is a two-tailed value from the t-distribution table corresponding to degree of freedom (df = n-1 , where n is the sample size) and the significance level (
) .
The given confidence interval = 99%
⇒ Significance level =

Sample size : n=3
DEgree of freedom : df = n-1 = 2
Then, the critical t- value for 99% confidence interval will be;

[From t-distribution table]
Hence, the appropriate percentile from a t-distribution for constructing the 99% confidence interval with n = 3 is 9.9248.