Question

A can of soda is placed inside a cooler. As the soda cools, its temperature T(x)

in degrees Celsius is given by the following function, where x
is the number of minutes since the can was placed in the cooler.

T(x)=−12+28e-0.38x

Find the initial temperature of the soda and its temperature after 18
minutes.
Round your answers to the nearest degree as necessary.

Answer 1

The initial temperature of the soda is 16°C

The temperature of the soda after 18 minutes is -12°C

Explanation:

T(x) = -12+28e^-0.38x

When x = 0

T(0) = -12+28e^-0.38(0) = -12+28e^0 = -12+28(1) = -12+28 = 16°C

Initial temperature of the soda is 16°C

When x = 18

T(18) = -12+28e^-0.38(18) = -12+28e^-6.84 = -12+28(0.0011) = -12+0.0308 = -11.9692°C = -12°C (to the nearest degree)

The temperature of the soda after 18 minutes is -12°C