Question

Yeast and other organisms can convert glucose (C6H12O6) to Ethanol (CH3CH2OH) through a process called Alcoholic Fermentation. The Net reaction is:

C6H12O6------2C2H5OH(l) +2CO2(g)

Calculate the mass of glucose required to produce 2.25L of CO2 measured at P=1 atm and T=295k

Answer 1

The answer to your question is 8.28 g of glucose

Step-by-step explanation:

Data

Glucose (C₆H₁₂O₆) = ?

Ethanol (CH₃CH₂OH)

Carbon dioxide (CO₂) = 2.25 l

Pressure = 1 atm

T = 295°K

Reaction

C₆H₁₂O₆ ⇒ 2C₂H₅OH(l) +2CO₂(g)

- Calculate the number of moles

PV = nRT

Solve for n

`n = (PV)/(RT)`

Substitution

`n = ((1)(2.25))/((0.082)(295))`

Simplification

n = 0.092

- Calculate the mass of glucose

1 mol of glucose --------------- 2 moles of carbon dioxide

x --------------- 0.092 moles

x = (0.092 x 1) / 2

x = 0.046 moles of glucose

Molecular weight of glucose = 180 g

180 g of glucose --------------- 1 mol

x g ---------------0.046 moles

x = (0.046 x 180) / 1

x = 8.28 g of glucose