Answer:
0.0035 mL of oxygen per hour is metabolic rate at 20°C at cockroach.
Step-by-step explanation:
- Metabolic rate of cockroaches at 15°C is 0.01 ml O2/h
- Metabolic rate of cockroaches at 25°C is 0.015 ml O2/hr
From the data we can see that metabolic rate of cockroach is in direct relation with temperature.

On graph, with metabolic rate on y-axis and temperature on x axis straight line will obtained , and the equation of the line can be determined by the help of point slope:

m = Slope of the line =

As per information given , :





x = temperature
y = metabolic rate
Now , put x = 20

y = 0.0035
0.0035 mL of oxygen per hour is metabolic rate at 20°C at cockroach.