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A particle's velocity is described by the function vx=kt2m/s, where vx is in m/s, t is in s, and k is a constant.

The particle's position at t0=0s is x0 = -8.10 m . At t1 = 2.00 s , the particle is at x1 = 8.00 m .

Determine the units of k in terms of m and s.

User Will Walsh
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1 Answer

3 votes

Answer:

ms^(-3)

Step-by-step explanation:

V = kt^2

m/s = k (s)^2

k = m/ s^(3)

k = ms^(-3)

User Pppery
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