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If the torque required to loosen a nut that is holding a flat tire in place on a car has a magnitude of 50 N·m, what minimum force must be exerted by the mechanic at the end of a 22 cm-long wrench to loosen the nut? Answer in units of N.

User Pndc
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1 Answer

4 votes

Answer:

227.27 N

Step-by-step explanation:

Torque: This can be defined as the force that tend to cause an object to twist or rotate. the torque of a body is also called moment of a body. The S.I unit of torque is N.m.

Mathematically

T = F×d ....................... Equation 1

Making F the subject of the equation,

F = T/d ..................... Equation 2

T = torque required to loosen the nut, F = force applied , d = distance between the force and the center of the nut.

Given: T = 50 N.m, d = 22 cm = (22/100) = 0.22 m.

F = 50/0.22

F = 227.27 N.

Thus the minimum force required to loosen the nut = 227.27 N

User Zaman
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