175k views
2 votes
Lightning As a crude model for lightning, consider the ground to be one plate of a parallel-plate capacitor and a cloud at an altitude of 650 m to be the other plate. Assume the surface area of the cloud to be the same as the area of a square that is 0.70 km on a side. a. What is the capacitance of this capacitor?b. How much charge can the cloud hold before the dielectric strength of the air is exceeded and a spark (lightning) results?

User Onur Uslu
by
7.7k points

1 Answer

0 votes

Answer:


6.67154* 10^(-9)\ F

13.009503 C

Step-by-step explanation:


\epsilon_0 = Permittivity of free space =
8.85* 10^(-12)\ F/m

k = Dielectric constant of air
3* 10^6\ V/m

Side of plate = 0.7 km

A = Area

d = Distance = 650 m

Capacitance is given by


C=(\epsilon_0A)/(d)\\\Rightarrow C=(8.85* 10^(-12)* 700^2)/(650)\\\Rightarrow C=6.67154* 10^(-9)\ F

The capacitance is
6.67154* 10^(-9)\ F

Electric field is given by


Q=CV\\\Rightarrow Q=Ckd\\\Rightarrow Q=6.67154* 10^(-9)* 3* 10^6* 650\\\Rightarrow Q=13.009503\ C

The charge on the cloud is 13.009503 C

User Hitesh Mundra
by
8.7k points