Question

Calculate the work engergy gained or lost by the system when a gas expands from 35 to 55 l against a constant external presure of 3atm.

Answer 1

Answer: The work energy lost by the system is -6078 Joules

Step-by-step explanation:

According to first law of thermodynamics:

`\Delta E=q+w`

`\Delta E`=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system=
`-P\Delta V` {Work is done by the system as the final volume is greater than initial volume and is negative}

where P = pressure = 3 atm

`\Delta V` = change in volume = (55-35) L = 20 L

w =
`-3atm* (20)L=-60Latm=-6078Joules`

{1Latm=101.3J}

Thus work energy lost by the system is -6078 Joules