Question

Monochromatic light falls on two very narrow slits 0.040 mm apart. Successive fringes on a screen 4.70 m away are 5.9 cm apart near the center of the pattern. What is the wavelength of the light?

Answer 1

λ = 502 n m

Step-by-step explanation:

given,

slit separation, d = 0.040 mm

= 4 x 10⁻⁵ m

Distance between the fringes, D = 4.70 m

distance between the fringes, x = 5.9 cm

= 0.059 m

wavelength of the light = ?

the separation between the fringe is given by

`x = (n\lambda\ D)/(d)`

`\lambda = (x d)/(n\ D)`

where as n = 1

`\lambda = (0.059* 4* 10^(-5))/(1* 4.70)`

λ = 5.02127 x 10⁻⁷ m

λ = 502 n m

hence, the wavelength of the light is equal to λ = 502 n m