Question

For the reaction below, calculate the number of moles of NH3 that would be formed when 5.5 moles of N2H4 reacts completely:3N2H4 --> 4NH3 + N2

Answer 1

7.33 moles of NH₃ are produced in the reaction.

Step-by-step explanation:

The reaction is this:

3 N₂H₄ → 4NH₃ + N₂

Ratio is 3:4

So 3 moles of N₂H₄ were needed to produce 4 moles of ammonia

5.5 moles of N₂H₄ would produce (5.5 . 4 ) / 3 = 7.33 moles of NH₃