Question

Find the 12th term of the geometric sequence 1, -4, 16,

Answer 1

a₁₂ = - 4194304

Explanation:

the nth term of a geometric sequence is

`a_(n)` = a₁
`(r)^(n-1)`

where a₁ is the first term and r the common ratio

here a₁ = 1 and r =
`(-4)/(1)` = - 4 , then

a₁₂ = 1 ×
`(-4)^(11)` = - 4194304