Question

A cyclist maintains a constant velocity of 4.1 m/s headed away from point A. At some initial time, the cyclist is 244 m from point A. What will be his displacement from his starting position after 60 s?

Answer 1

`d=490\ m` is his final displacement from the point A after 60 seconds.

Step-by-step explanation:

Given:

Cyclist is moving away from A.

• velocity of cyclist,
  `v=4.1\ m.s^(-1)`

• displacement of the cyclist from point A at the time of observation,
  `d_i=244\ m`

• time after which the next observation is to be recorded,
  `t=60\ s`

Now as the cyclist is moving away from point A his change in displacement after the mentioned time:

`\Delta d=v.t`

`\Delta d = 4.1 * 60`

`\Delta d=246\ m`

Now the the final displacement from point A after the mentioned time:

`d=d_i+\Delta d`

`d=244+246`

`d=490\ m`