Question

Given the following reaction:


`C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O`
How many moles of CO₂ ​will be produced from 79.0 g of C₃H₈, assuming O₂ is available in excess?

Answer 1

5.38 moles of CO₂ are produced

Step-by-step explanation:

This is the reaction:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

First of all, let's convert the mass of C₃H₈ to moles (mass / molar mass)

79 g / 44 g/mol = 1.79 moles

So ratio is 1:3.

1 mol of C₃H₈ is needed to produce 3 moles of CO₂

1.79 moles of C₃H₈ would produce (1.79 .3) /1 = 5.38 moles