Question

The snowblower driver figured that he moved 1250 kg of snow. If the plow pushes with a force of 40000 Newton’s, how fast did the snow accelerate? (Assume no friction)

Answer 1

The acceleration of snow is 32 m/
`s^(2)`.

Step-by-step explanation:

According to Newton's second law of motion, the force acting on any object is directly proportional to the product of mass and acceleration acting on the object.

So if the object is a snowblower driver with mass 1250 kg and the force acting on it is 40000 N, then the acceleration of the snow can be determined from the ratio of force to mass.

Force = Mass × Acceleration

Acceleration =
`(Force)/(Mass)` =
`(40000)/(1250)=32 m/s^(2)`

Thus, the acceleration of the snow is 32 m/
`s^(2)`.